查看完整版本 : Partial Derivative (1D)

xianrenb 2022-5-18 14:48

想到以下“古怪”的計算:
[url=https://gist.github.com/xianrenb/2926df0667b2c18423a9c3835e655219]https://gist.github.com/xianrenb/2926df0667b2c18423a9c3835e655219[/url]
∂u/∂x = +/- sqrt((du)^2/(dx^2 + x d^2x))

唔知有無算錯。

xianrenb 2022-5-19 09:24

[quote]原帖由 [i]xianrenb[/i] 於 2022-5-18 14:48 發表 [url=https://www.discuss.com.hk/redirect.php?goto=findpost&pid=548603716&ptid=30582085][img]https://www.discuss.com.hk/images/common/back.gif[/img][/url]
想到以下“古怪”的計算:
https://gist.github.com/xianrenb/2926df0667b2c18423a9c3835e655219
∂u/∂x = +/- sqrt((du)^2/(dx^2 + x d^2x))

唔知有無算錯。 [/quote]
算是算錯了一點,修正成 rev. 2 :
[url=https://gist.github.com/xianrenb/2926df0667b2c18423a9c3835e655219]https://gist.github.com/xianrenb/2926df0667b2c18423a9c3835e655219[/url]
d(((∂u/∂x)^2 (d(x dx/du)) - du)/((∂u/∂x)^2 d(dx/du))) = 0

xianrenb 2022-5-19 11:05

[quote]原帖由 [i]xianrenb[/i] 於 2022-5-19 09:24 發表 [url=https://www.discuss.com.hk/redirect.php?goto=findpost&pid=548625823&ptid=30582085][img]https://www.discuss.com.hk/images/common/back.gif[/img][/url]

算是算錯了一點,修正成 rev. 2 :
https://gist.github.com/xianrenb/2926df0667b2c18423a9c3835e655219
d(((∂u/∂x)^2 (d(x dx/du)) - du)/((∂u/∂x)^2 d(dx/du))) = 0 [/quote]
補充計算,算出 x 及 dx ,更新成 rev. 3 :
[url=https://gist.github.com/xianrenb/2926df0667b2c18423a9c3835e655219]https://gist.github.com/xianrenb/2926df0667b2c18423a9c3835e655219[/url]
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查看完整版本: Partial Derivative (1D)